At 10 $\circ$ C one volume of water dissolves 3.10 volumes of chlorine gas at 1.00 atm pressure.What is the Henry's Law constant in mol/L·atm?
A)3.8
B)0.043
C)36.
D)3.1
E)0.13

Question

Quizplus · Accepted Answer

Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid. The constant can be calculated using the formula $k_H = \frac{C}{P}$, where $C$ is the concentration of the gas in the liquid and $P$ is the pressure. Given that 3.10 volumes of chlorine gas dissolve in one volume of water at 1 atm, the concentration is 3.10 mol/L, so $k_H = \frac{3.10}{1} = 3.10$. However, the correct constant should be calculated considering the molar volume of gas at standard conditions, leading to the correct choice of 0.13 mol/L·atm.

At 10 ∘\circ∘ C One Volume of Water Dissolves 3

At 10^$\circ$C One Volume of Water Dissolves 3