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Consider the Following Linear Program Objective Function Value = 20

Question 61

Essay

Consider the following linear program:
 Max 3x1+4x2 ($ Profit)  s.t. x1+3x2122x1+x28x13x1,x20\begin{array} { c c } \text { Max } & 3 x _ { 1 } + 4 x _ { 2 } \text { (\$ Profit) } \\\text { s.t. } & x _ { 1 } + 3 x _ { 2 } \leq 12 \\& 2 x _ { 1 } + x _ { 2 } \leq 8 \\& x _ { 1 } \leq 3 \\& x _ { 1 } , x _ { 2 } \geq 0\end{array}
Objective Function Value = 20.000  Variable  Value  Reduced Cost  X1 2.4000.000 X2 3.2000.000\begin{array} { c c c } \text { Variable } & \text { Value } & \text { Reduced Cost } \\\text { X1 } & 2.400 & 0.000 \\\text { X2 } & 3.200 & 0.000\end{array}  Constraint  Slack/Surplus  Dual Price 10.0001.00020.0001.00030.6000.000\begin{array} { c c c } \text { Constraint } & \text { Slack/Surplus } & \text { Dual Price } \\1 & 0.000 & 1.000 \\2 & 0.000 & 1.000 \\3 & 0.600 & 0.000\end{array} OBJECTIVE COEFFICIENT RANGES  Variable  Lower Limit  Current Value  Upper Limit  X1 1.3333.0008.000 X2 1.5004.0009.000\begin{array} { c c c c } \text { Variable } & \text { Lower Limit } & \text { Current Value } & \text { Upper Limit } \\\text { X1 } & 1.333 & 3.000 & 8.000 \\\text { X2 } & 1.500 & 4.000 & 9.000\end{array} RIGHT HAND SIDE RANGES  Constraint  Lower Limit  Current Value  Upper Limit 19.00012.00024.00024.0008.0009.00032.4003.000 No Upper Limit \begin{array} { c c c c } \text { Constraint } & \text { Lower Limit } & \text { Current Value } & \text { Upper Limit } \\1 & 9.000 & 12.000 & 24.000 \\2 & 4.000 & 8.000 & 9.000 \\3 & 2.400 & 3.000 & \text { No Upper Limit }\end{array}
a.What is the optimal solution including the optimal value of the objective function?
b.Suppose the profit on x1 is increased to $7. Is the above solution still optimal? What is the value of the objective function when this unit profit is increased to $7?
c.If the unit profit on x2 was $10 instead of $4, would the optimal solution change?
d.If simultaneously the profit on x1 was raised to $5.5 and the profit on x2 was reduced to $3, would the current solution still remain optimal?

Correct Answer:

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a.x1 = 2.4 and x2 = 3.2,and obj.func.= $20...

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