A mixture of three gases has a total pressure of 1,380 mmHg at 298 K. The mixture is analyzed and is found to contain 1.27 mol CO₂, 3.04 mol CO, and 1.50 mol Ar. What is the partial pressure of Ar A) 0.258 atm B) 301 mmHg C) 356 mmHg D) 5,345 mmHg E) 8,020 mmHg

Question

Quizplus · Accepted Answer

The partial pressure of Ar can be found using the equation:
P Ar = (n Ar /n total ) x P total 
where n Ar is the number of moles of Ar and n total is the total number of moles of gas in the mixture. 
Substituting the given values, we have:
n Ar = 1.50 mol 
n CO = 3.04 mol 
n COS = 1.27 mol 
n total = 5.81 mol 
P total = 1380 mmHg 
Therefore, 
P Ar = (1.50/5.81) x 1380 
P Ar = 356 mmHg
Thus, the correct answer is C.

A Mixture of Three Gases Has a Total Pressure of 1,380