Calculate the density of Ar(g) at -11^$\circ$C and 675 mmHg. A) -39.3 g/L B) 1.52g/L C) 1.65 g/L D) 39.95 g/L E) 1254 g/L

Question

Quizplus · Accepted Answer

To calculate the density of Ar(g), use the ideal gas law: PV = nRT. Convert temperature to Kelvin (262 K) and pressure to atm (0.888 atm). Use the molar mass of Ar (39.95 g/mol) and R = 0.0821 L·atm/mol·K. Density = (P * M) / (R * T) = (0.888 atm * 39.95 g/mol) / (0.0821 L·atm/mol·K * 262 K) = 1.65 g/L.

Calculate the Density of Ar(g) at -11 ∘\circ∘ C and 675 MmHg

Calculate the Density of Ar(g) at -11^$\circ$C and 675 MmHg