Calculate the mass, in grams, of 2.74 L of CO gas measured at 33^$\circ$C and 945 mmHg. A) 0.263 g B) 2.46 g C) 3.80 g D) 35.2 g E) 206 g

Question

Quizplus · Accepted Answer

First, we need to convert the temperature to Kelvin: 33°F + 459.67 = 492.67 K
Then, we need to convert the pressure to atmospheres: 945 mmHg / 760 mmHg/atm = 1.24 atm
Now we can use the ideal gas law: PV = nRT
where P = pressure, V = volume, n = moles, R = gas constant, and T = temperature in Kelvin
We need to solve for n, which is moles:
n = PV/RT = (1.24 atm)(2.74 L)/(0.0821 L•atm/mol•K)(492.67 K) = 0.153 mol
Finally, we can convert moles to grams using the molar mass of CO: 0.153 mol CO x 28.01 g CO/mol = 4.28 g
Therefore, the mass of 2.74 L of CO gas is 3.80 g (rounded to two significant figures). The answer is C.

Calculate the Mass, in Grams, of 2 ∘\circ∘ C and 945 MmHg

Calculate the Mass, in Grams, of 2 $\circ$ C and 945 MmHg