A gas evolved during the fermentation of sugar was collected. After purification its volume was found to be 25.0 L at 22.5^$\circ$C and 702 mmHg. How many moles of gas were collected A) 0.95 mol B) 1.05 mol C) 12.5 mol D) 22.4 mol E) 724 mol

Question

Quizplus · Accepted Answer

To find the moles of gas collected, we can use the ideal gas law equation, PV = nRT, where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/(mol·K)), and T is the temperature in Kelvin. First, convert the given temperature from Celsius to Kelvin (T = 10 + 273.15 = 283.15 K) and the pressure from mmHg to atm (702 mmHg * (1 atm / 760 mmHg) ≈ 0.924 atm). Then, solve for n: n = PV / RT = (0.924 atm * 25.0 L) / (0.0821 L·atm/(mol·K) * 283.15 K) ≈ 0.95 mol.

A Gas Evolved During the Fermentation of Sugar Was Collected ∘\circ∘

A Gas Evolved During the Fermentation of Sugar Was Collected $\circ$