The boiling points of propanol (CH₃CH₂CH₂OH) and pentanol (CH₃CH₂CH₂CH₂CH₂OH) are 97^$\circ$C and 137^$\circ$C, respectively. The boiling point of butanol (CH₃CH₂CH₂CH₂OH) is predicted to be: A) 137^$\circ$C C) 97^$\circ$C and

Question

The boiling points of propanol (CH₃CH₂CH₂OH) and pentanol (CH₃CH₂CH₂CH₂CH₂OH) are 97^$\circ$C and 137^$\circ$C, respectively. The boiling point of butanol (CH₃CH₂CH₂CH₂OH) is predicted to be: A) < 97^$\circ$C B) > 137^$\circ$C C) > 97^$\circ$C and < 137^$\circ$C D) 97^$\circ$C E) 137^$\circ$C

Quizplus · Accepted Answer

To predict which compound has a higher boiling point, we need to look at their molecular structures and intermolecular forces of attraction. We see that as we go from propanol to pentanol, the molecular size and complexity increases, leading to more intermolecular forces of attraction between the molecules. This results in an increase in boiling point from 97°C to 137°C.

Butanol is in between propanol and pentanol in terms of molecular size and complexity. Thus, we can predict that it will have a boiling point higher than that of propanol but lower than pentanol. Therefore, the correct answer is C - > 97°C and < 137°C.

The Boiling Points of Propanol (CH3CH2CH2OH) and Pentanol (CH3CH2CH2CH2CH2OH) Are ∘\circ∘

The Boiling Points of Propanol (CH₃CH₂CH₂OH) and Pentanol (CH₃CH₂CH₂CH₂CH₂OH) Are $\circ$