A solution is prepared by adding 6.24 g of benzene (C₆H₆, 78.11 g/mol) to 80.74 g of cyclohexane (C₆H₁₂, 84.16 g/mol). Calculate the mole fraction and molality of benzene in this solution. A) Mole fraction = 0.0769; molality = 0.789 m B) Mole fraction = 0.0869; molality = 0.789 m C) Mole fraction = 0.0769; molality = 0.989 m D) Mole fraction = 0.0869; molality = 0.989 m E) None of the above

Question

Quizplus · Accepted Answer

The Answer of A solution is prepared by adding 6.24 g of benzene (C₆H₆, 78.11 g/mol) to 80.74 g of cyclohexane (C₆H₁₂, 84.16 g/mol). Calculate the mole fraction and molality of benzene in this solution. A) Mole fraction = 0.0769; molality = 0.789 m B) Mole fraction = 0.0869; molality = 0.789 m C) Mole fraction = 0.0769; molality = 0.989 m D) Mole fraction = 0.0869; molality = 0.989 m E) None of the above

A Solution Is Prepared by Adding 6