What is the molarity of a solution that is 5.50 % by mass oxalic acid (C₂H₂O₄) and has a density of 1.0244 g/mL A) 0.626 M B) 0.646 M C) 0.666 M D) 0.686 M E) None of the above

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The correct answer is A because the molarity of the solution can be calculated using the formula:Molarity = (Mass of solute / Molar mass of solute) / Volume of solutionThe mass of solute can be calculated using the percentage by mass and the density of the solution:Mass of solute = (5.50 g / 100 g) * 1000 mL * 1.0244 g/mL = 56.34 gThe molar mass of oxalic acid is 90.03 g/mol.The volume of solution can be calculated using the density and the mass of the solution:Volume of solution = 1000 mL / 1.0244 g/mL = 976.7 mLTherefore, the molarity of the solution is:Molarity = (56.34 g / 90.03 g/mol) / 0.9767 L = 0.626 M

What Is the Molarity of a Solution That Is 5