The normal boiling point of acetic acid is 118.1^$\circ$C. If a sample of the acetic acid is at 125.2^$\circ$C, predict the signs of $\Delta$H, $\Delta$S, and $\Delta$G for the boiling process at this temperature. A) ($\Delta$H) 0, $\Delta$S 0, $\Delta$G 0, $\Delta$S 0, $\Delta$G 0 C) ($\Delta$H) 0, $\Delta$S

Question

The normal boiling point of acetic acid is 118.1^$\circ$C. If a sample of the acetic acid is at 125.2^$\circ$C, predict the signs of $\Delta$H, $\Delta$S, and $\Delta$G for the boiling process at this temperature. A) ($\Delta$H) > 0, $\Delta$S > 0, $\Delta$G < 0 B) ($\Delta$H) > 0, $\Delta$S > 0, $\Delta$G > 0 C) ($\Delta$H) > 0, $\Delta$S < 0, $\Delta$G < 0 D) ($\Delta$H) < 0, $\Delta$S > 0, $\Delta$G > 0 E) ($\Delta$H) < 0, $\Delta$S < 0, $\Delta$G > 0

Quizplus · Accepted Answer

Since the sample of acetic acid is at a temperature higher than its normal boiling point, the boiling process is not spontaneous, and as a result, the entropy change will be positive (F1F1F1S1F1F1F10S > 0). The enthalpy change will be positive because energy needs to be added in order to raise the temperature of the sample to the boiling point (F1F1F1S1F1F1F10H > 0). The Gibbs free energy change will be negative because the process is non-spontaneous, so the free energy of the system increases (F1F1F1S1F1F1F10G < 0). Therefore, the best choice is A.

The Normal Boiling Point of Acetic Acid Is 118 ∘\circ∘ C If a Sample of the Acetic Acid Is at C

The Normal Boiling Point of Acetic Acid Is 118 $\circ$ C If a Sample of the Acetic Acid Is at C