The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II) oxide: HgO(s) $\rarr$ Hg(l) + ¹/₂O₂(g) , $\Delta$ H^$\circ$ = 90.84 kJ/mol.Estimate the temperature at which this reaction will become spontaneous under standard state conditions.S^$\circ$(Hg) = 76.02 J/K·mol
S^$\circ$(O₂) = 205.0 J/K·mol
S^$\circ$(HgO) = 70.29 J/K·mol

Question

The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II) oxide: HgO(s)

\rarr

Hg(l) + ¹/₂O₂(g) ,

\Delta

H^$\circ$ = 90.84 kJ/mol.Estimate the temperature at which this reaction will become spontaneous under standard state conditions.S^$\circ$(Hg) = 76.02 J/K·mol
S^$\circ$(O₂) = 205.0 J/K·mol
S^$\circ$(HgO) = 70.29 J/K·mol

Quizplus · Accepted Answer

The Answer of The element oxygen was prepared by Joseph Priestley in 1774 by heating mercury(II) oxide: HgO(s) $\rarr$ Hg(l) + ¹/₂O₂(g), $\Delta$H^$\circ$ = 90.84 kJ/mol.Estimate the temperature at which this reaction will become spontaneous under standard state conditions.S^$\circ$(Hg) = 76.02 J/K·mol S^$\circ$(O₂) = 205.0 J/K·mol S^$\circ$(HgO) = 70.29 J/K·mol A) 108 K B) 430 K C) 620 K D) 775 K E) 840 K

The Element Oxygen Was Prepared by Joseph Priestley in 1774 →\rarr→

The Element Oxygen Was Prepared by Joseph Priestley in 1774 $\rarr$