Consider the following work breakdown structure: $\begin{array}{r}
{\text { Time Estimates (wks) }} \
\begin{array}{lccccc}
& \text { Start } & \text { Finish } \
\text { Activity } & \text { Node } \quad\quad& \text { Node } \quad\quad& \mathrm{t}_{0} \quad\quad& \mathrm{t}_{\mathrm{m}} \quad& \mathrm{t}_{\mathrm{p}} \quad\
\hline \text { A } & 1 & 2 & 11 & 20 & 29 \
\text { B } & 2 & 3 & 2 & 5 & 8 \
\text { C } & 2 & 4 & 18 & 30 & 42 \
\text { D } & 3 & 4 & 7 & 10 & 13 \
\text { E } & 1 & 4 & 31 & 40 & 43
\end{array}\end{array}$ What is the estimated standard deviation in the time for activity E?
A) 0 weeks
B) 1 week
C) 2 weeks
D) 3 weeks
E) 4 weeks

Question

Quizplus · Accepted Answer

To find the estimated standard deviation in the time for activity E, we need to use the following formula:

σ = (t_p - t_0) / 6

where σ is the estimated standard deviation, t_p is the pessimistic time estimate, and t_0 is the optimistic time estimate.

From the table, we can see that for activity E, t_p = 43 and t_0 = 31. Therefore,

σ = (43 - 31) / 6 = 2

So the estimated standard deviation in the time for activity E is 2 weeks. Therefore, the best choice is C.

Consider the Following Work Breakdown Structure What Is the Estimated Standard Deviation in the Time for (wks)