The Mean Free Path of a Molecule Is 2 $\times$ 10^-7 M in an Ideal Gas at Standard Temperature and 10^-7

The mean free path of a molecule is 2.25 $\times$ 10^-7 m in an ideal gas at standard temperature and pressure.What is the mean free path when the pressure of the gas is doubled and the temperature is tripled?

A) 0.75 $\times$ 10^-7m
B) 1.13 $\times$ 10^-7m
C) 2.25 $\times$ 10^-7m
D) 3.38 $\times$ 10^-7m
E) 3.75 $\times$ 10^-7m