The mean free path of a molecule is 2.25 $\times$ 10^-7 m in an ideal gas at standard temperature and pressure.What is the mean free path when the diameter of the molecule is doubled? A) 0.23 $\times$ 10^-7m B) 0.45 $\times$ 10^-7m C) 0.56 $\times$ 10^-7m D) 0 75 $\times$ 10^-7m E) 1.13 $\times$ 10^-7m

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The Answer of The mean free path of a molecule is 2.25 $\times$ 10^-7 m in an ideal gas at standard temperature and pressure.What is the mean free path when the diameter of the molecule is doubled? A) 0.23 $\times$ 10^-7m B) 0.45 $\times$ 10^-7m C) 0.56 $\times$ 10^-7m D) 0 75 $\times$ 10^-7m E) 1.13 $\times$ 10^-7m

The Mean Free Path of a Molecule Is 2 ×\times× 10-7 M in an Ideal Gas at Standard Temperature and 10-7

The Mean Free Path of a Molecule Is 2 $\times$ 10^-7 M in an Ideal Gas at Standard Temperature and 10^-7