A molecule in an ideal gas has an rms velocity 450 m/s.If the mean free path of the particle in the gas is 5.00 $\times$ 10^-8 m,then what is the average time between collisions? A) 1.11 $\times$ 10^-10 sec B) 1.98 $\times$ 10^-10 sec C) 2.03 $\times$ 10^-10 sec D) 2.56 $\times$ 10^-10 sec E) 3.03 $\times$ 10^-10 sec

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Quizplus · Accepted Answer

The average time between collisions is given by the mean free path divided by the rms velocity. So, the average time between collisions is:$$t = \frac{\lambda}{v_{rms}} = \frac{5.00 	imes 10^{-8} 	ext{ m}}{450 	ext{ m/s}} = 1.11 	imes 10^{-10} 	ext{ s}$$

A Molecule in an Ideal Gas Has an Rms Velocity ×\times×

A Molecule in an Ideal Gas Has an Rms Velocity $\times$