An ideal gas is at a temperature of 40$^{\circ}$C and a pressure of 2.00 atmospheres.If the diameter of an N₂ molecule is 0.300 nm,then what is the mean free path of the N₂ molecule in the gas? A) 6.02 $\times$ 10^-8 m B) 5.33 $\times$ 10^-8 m C) 5.00 $\times$ 10^-8 m D) 4.75 $\times$ 10^-8 m E) 4.01 $\times$ 10^-8 m

Question

Quizplus · Accepted Answer

The mean free path $\lambda$ is calculated using the formula $\lambda = \frac{kT}{\sqrt{2} \pi d^2 P}$, where $k$ is the Boltzmann constant, $T$ is the temperature in Kelvin, $d$ is the diameter of the molecule, and $P$ is the pressure. Converting 40°C to Kelvin and substituting the given values into the formula gives the mean free path as approximately 5.33 * 10^-8 m.

An Ideal Gas Is at a Temperature of 40 ∘^{\circ}∘ C and a Pressure of 2

An Ideal Gas Is at a Temperature of 40 $^{\circ}$ C and a Pressure of 2