What is the change in the boiling point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into 150.0 ml of water? The density of water is and . A)0.502°C B)5.22°C C)0.0418°C D)0.279°C E)none of the above

Question

Quizplus · Accepted Answer

First, we need to calculate the molality of the solution:
molality = (moles of solute) / (mass of solvent in kg)
moles of solute = (14.7 g) / (114.22 g/mol) = 0.1286 mol
mass of solvent = (150.0 mL) x (1.00 g/mL) = 150.0 g = 0.150 kg
molality = 0.1286 mol / 0.150 kg = 0.857 mol/kg

Next, we need to calculate the change in boiling point using the equation:
ΔTb = Kb x molality
where Kb is the molal boiling point elevation constant for water, which is 0.512 °C/m.

ΔTb = (0.512 °C/m) x (0.857 mol/kg) = 0.439 °C

Therefore, the change in boiling point of the solution is 0.439 °C, which is closest to choice letter D.

What Is the Change in the Boiling Point of a Solution