What volume of 12.0 M HCl is required to make 75.0 mL of 3.50 M HCl?
A)21.9 mL
B)0.560 mL
C)257 mL
D)560.mL
E)none of the above

Question

Quizplus · Accepted Answer

Use the dilution formula:

M1V1 = M2V2

Where:

M1 = 12.0 M (initial concentration)
V1 = unknown (volume of 12.0 M HCl to be used)
M2 = 3.50 M (final concentration)
V2 = 75.0 mL (final volume)

Solving for V1:

V1 = (M2 x V2) / M1

V1 = (3.50 M x 75.0 mL) / 12.0 M

V1 = 21.9 mL

Therefore, the answer is A) 21.9 mL

What Volume of 12