Glycerin, with a viscosity of 1.50 Ns/m², is flowing with an average speed of 1.20 m/s through a tube that has a radius of 5.00 mm and is 25.0 cm long. What is the drop in pressure? A) 144 kPa B) 45.8 kPa C) 72.0 kPa D) 76.3 kPa E) 129 kPa

Question

Quizplus · Accepted Answer

The correct answer is A because the drop in pressure is given by the equation ΔP = 8ηLv/r^4, where η is the viscosity, L is the length of the tube, v is the average speed of the fluid, and r is the radius of the tube. Plugging in the given values, we get ΔP = 8(1.50 Ns/m^2)(0.250 m)(1.20 m/s)/(5.00 x 10^-3 m)^4 = 144 kPa.

Glycerin, with a Viscosity of 1