When 2.77 g of a solute was dissolved in 25.0 g of water,the resulting solution had a freezing point of -3.06°C.What is the apparent molar mass of the solute? K_f of water is 1.86°C/m. A)36.2 g/mol B)67.3 g/mol C)227 g/mol D)82.2 g/mol E)1.65 g/mol

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Quizplus · Accepted Answer

The freezing point depression is calculated using ΔTf = i * Kf * m, where ΔTf is the change in freezing point, Kf is the cryoscopic constant, and m is the molality. Here, ΔTf = 3.06°C, Kf = 1.86°C/m, and m = moles of solute/kg of solvent. Solving for moles of solute and using the mass of solute, the apparent molar mass is calculated to be approximately 67.3 g/mol.

When 277 G of a Solute Was Dissolved in 25