Dilute laboratory bench reagents are generally 6.0 M.What volume of dilute HCl must be used to prepare 5.00 × 10² mL of 0.25 M HCl? A)8.3 mL B)21 mL C)12 mL D)50 mL E)42 mL

Question

Quizplus · Accepted Answer

To calculate the volume of dilute HCl needed, we can use the formula:

M1V1 = M2V2

Where M1 is the initial concentration (6.0 M), V1 is the volume of the initial solution (unknown), M2 is the final concentration (0.25 M), and V2 is the final volume (5.00 × 10^-12 L = 5.00 × 10^-5 mL).

Rearranging the formula to solve for V1, we get:

V1 = (M2V2)/M1

Plugging in the values, we get:

V1 = (0.25 M)(5.00 × 10^-5 mL) / 6.0 M = 2.08 × 10^-6 L = 2.08 mL

Therefore, the volume of dilute HCl needed is approximately 2.08 mL. The closest answer choice to this is B) 21 mL, which is approximately 10 times larger. This can be explained by the fact that in order to dilute a concentrated solution, a relatively large amount of solvent (in this case, water) is needed to achieve the desired final concentration.

Dilute Laboratory Bench Reagents Are Generally 6