What is the molality of a solution made by dissolving 12.73 g of CH₃OH in 87.27 g of water? A)6.855 m B)4.552 m C)3.977 m D)1.273 m E)0.1273 m

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Quizplus · Accepted Answer

Molality (m) is calculated using the formula: molality = moles of solute / kilograms of solvent. First, calculate the molar mass of CH3OH (which seems to be the intended compound, given the typo): Carbon (C) = 12.01 g/mol, Hydrogen (H) = 1.01 g/mol × 4, Oxygen (O) = 16.00 g/mol. Total molar mass = 12.01 + (4 × 1.01) + 16.00 = 32.05 g/mol. Moles of CH3OH = 12.73 g / 32.05 g/mol = 0.397 moles. Kilograms of water = 87.27 g = 0.08727 kg. Molality = 0.397 moles / 0.08727 kg = 4.552 m.

What Is the Molality of a Solution Made by Dissolving