How many grams of Ba(OH)₂ are needed to prepare 2.50 liters of 0.200 M barium hydroxide solution? A)85.7 g B)77.2 g C)34.3 g D)13.7 g E)171.3 g

Question

Quizplus · Accepted Answer

The molar mass of Ba(OH)2 is 171.34 g/mol. To find the number of grams needed, we can use the following formula:

grams = (moles) x (molar mass)

First, we need to determine the number of moles in 2.50 L of 0.200 M Ba(OH)2 solution.

moles = M x V

moles = 0.200 mol/L x 2.50 L

moles = 0.500 mol

Now we can use the formula to solve for grams:

grams = (0.500 mol) x (171.34 g/mol)

grams = 85.7 g

Therefore, the answer is A) 85.7 g.

How Many Grams of Ba(OH)2 Are Needed to Prepare 2