A body is projected vertically upwards and moves so that $s=u t-16 t^{2}$, where $s$ is the distance ( $\left.\mathrm{m}\right), t$ is the time $(\mathrm{s})$, and $u$ is the initial velocity of the body $(\mathrm{m} / \mathrm{s})$. Find the time it takes for a body to rise 275 metres, if its initial velocity is $150 \mathrm{~m} / \mathrm{s}$.

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The Answer of A body is projected vertically upwards and moves so that $s=u t-16 t^{2}$, where $s$ is the distance ( $\left.\mathrm{m}\right), t$ is the time $(\mathrm{s})$, and $u$ is the initial velocity of the body $(\mathrm{m} / \mathrm{s})$. Find the time it takes for a body to rise 275 metres, if its initial velocity is $150 \mathrm{~m} / \mathrm{s}$.

A Body Is Projected Vertically Upwards and Moves So That s=ut−16t2s=u t-16 t^{2}s=ut−16t2

A Body Is Projected Vertically Upwards and Moves So That $s=u t-16 t^{2}$