When resistors $R_{a}$ and $R_{b}$ are in series, the equivalent resistance $R=R_{a}+R_{b}$. When resistors $R_{a}$ and $R_{b}$ are in parallel, the equivalent resistance $R$ satisfies $\frac{1}{R}=\frac{1}{R_{a}}+\frac{1}{R_{b}}$. In the diagram below, $R_{1}=R_{2}$ and $R_{3}=100 \Omega$. The equivalent resistance for all three resistors is $120 \Omega$. What is the value of $R_{1}$ and $R_{2}$ ?

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The Answer of When resistors $R_{a}$ and $R_{b}$ are in series, the equivalent resistance $R=R_{a}+R_{b}$. When resistors $R_{a}$ and $R_{b}$ are in parallel, the equivalent resistance $R$ satisfies $\frac{1}{R}=\frac{1}{R_{a}}+\frac{1}{R_{b}}$. In the diagram below, $R_{1}=R_{2}$ and $R_{3}=100 \Omega$. The equivalent resistance for all three resistors is $120 \Omega$. What is the value of $R_{1}$ and $R_{2}$ ?

When Resistors RaR_{a}Ra​ And RbR_{b}Rb​ Are in Series, the Equivalent Resistance R=Ra+RbR=R_{a}+R_{b}R=Ra​+Rb​ When Resistors

When Resistors $R_{a}$ And $R_{b}$ Are in Series, the Equivalent Resistance $R=R_{a}+R_{b}$ When Resistors