The length of the diagonal of a box is given by $\mathrm{D}=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}$ where $\mathrm{L}, \mathrm{W}$, and $\mathrm{H}$ are the length, width, and height of the box. Find the length of the diagonal, $\mathrm{D}$, of a box that is $4 \mathrm{ft}$ long, $2 \mathrm{ft}$ high, and $4 \mathrm{ft}$ wide. Give the exact value.
A) $32 \mathrm{ft}$
B) $10 \mathrm{ft}$
C) $4 \sqrt{2} \mathrm{ft}$
D) $6 \mathrm{ft}$

Question

Quizplus · Accepted Answer

The diagonal is calculated as $D = \sqrt{4^2 + 4^2 + 2^2} = \sqrt{16 + 16 + 4} = \sqrt{36} = 6 \mathrm{ft}$.

The Length of the Diagonal of a Box Is Given D=L2+W2+H2\mathrm{D}=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}D=L2+W2+H2​

The Length of the Diagonal of a Box Is Given $\mathrm{D}=\sqrt{\mathrm{L}^{2}+\mathrm{W}^{2}+\mathrm{H}^{2}}$