The length of the diagonal of a rectangle is given by $D=\sqrt{L^{2}+W^{2}}$ where $L$ and $W$ are the length and width of the rectangle. What is the length of the diagonal, $\mathrm{D}$, of a rectangle that is 98 inches long and 49 inches wide? Round your answer to the nearest tenth of an inch, if necessary.
A) 69.3 in.
B) 109.6 in.
C) 84.9 in.
D) $12.1 \mathrm{in}$.

Question

Quizplus · Accepted Answer

Using the formula $D=\sqrt{L^{2}+W^{2}}$, substitute $L=98$ and $W=49$ to get $D=\sqrt{98^{2}+49^{2}}$, which simplifies to $D=\sqrt{9604+2401}=\sqrt{12005}$, and further to approximately 109.6 inches.

The Length of the Diagonal of a Rectangle Is Given D=L2+W2D=\sqrt{L^{2}+W^{2}}D=L2+W2​

The Length of the Diagonal of a Rectangle Is Given $D=\sqrt{L^{2}+W^{2}}$