Factor the trinomial completely.
-$x^{2} y^{2}+12 x y+35$
A) $(x y-7)(x y-5)$
B) $(x y+7)(x y-5)$
C) $\left(x^{2}+7\right)\left(y^{2}+5\right)$
D) $(x y+7)(x y+5)$

Question

Quizplus · Accepted Answer

The trinomial can be factored as a product of two binomials where both terms are positive, matching option D: $(x y+7)(x y+5)$. This is because $7 + 5 = 12$ and $7 \times 5 = 35$, which aligns with the middle term and constant term of the original trinomial, respectively.

Factor the Trinomial Completely x2y2+12xy+35x^{2} y^{2}+12 x y+35x2y2+12xy+35 A) (xy−7)(xy−5)(x y-7)(x y-5)(xy−7)(xy−5)

Factor the Trinomial Completely $x^{2} y^{2}+12 x y+35$ A) $(x y-7)(x y-5)$