Factor the trinomial completely.
-$-x^{2}-2 x+63$
A) $-(x-7)(x+9)$
B) Prime
C) $-(x-7)(x-9)$
D) $(x+7)(x-9)$

Name: Factor the trinomial completely. -$-x^{2}-2 x+63$ A) $-(x-7)(x+9)$ B) Prime C) $-(x-7)(x-9)$ D) $(x+7)(x-9)$
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Quizplus · Accepted Answer

The trinomial $-x^{2}-2 x+63$ can be factored by first factoring out the negative sign, giving $-1(x^{2}+2x-63)$. Then, finding two numbers that multiply to -63 and add to 2, which are 9 and -7, we get $-(x-7)(x+9)$.

Factor the Trinomial Completely −x2−2x+63-x^{2}-2 x+63−x2−2x+63 A) −(x−7)(x+9)-(x-7)(x+9)−(x−7)(x+9) B) Prime C) −(x−7)(x−9)-(x-7)(x-9)−(x−7)(x−9) D) (x+7)(x−9)(x+7)(x-9)(x+7)(x−9)

Factor the Trinomial Completely $-x^{2}-2 x+63$ A) $-(x-7)(x+9)$ B) Prime
C) $-(x-7)(x-9)$ D) $(x+7)(x-9)$