Question 1

Evaluate.
-$\frac{1}{3} \div(-8)$
A) $-\frac{8}{3}$
B) -24
C) $\frac{1}{24}$
D) $-\frac{1}{24}$

Accepted Answer

Dividing by a negative number flips the sign, so $\frac{1}{3} \div(-8) = -\frac{1}{3} \times \frac{1}{8} = -\frac{1}{24}$.

Question 2

Evaluate.
-$-19+(-10)+(-10)+21$
A) 60
B) -18
C) 22
D) 18

Accepted Answer

Adding the numbers gives: $-19 + (-10) + (-10) + 21 = -38 + 21 = -17$, which is not an option. However, the closest correct calculation should be $-19 - 10 - 10 + 21 = -18$, indicating a possible typo in the question or answer choices.

Question 3

Evaluate.
-$2+(-12)-(-14)$
A) 0
B) -4
C) -24
D) 4

Accepted Answer

The expression simplifies to $2 - 12 + 14$, which equals $4$.

Question 4

Evaluate.
-$3-(-3) \cdot(-2)^{3}$
A) -21
B) -48
C) 48
D) 21

Accepted Answer

First, calculate the exponent: $(-2)^3 = -8$. Then, multiply by $-3$: $-3 \cdot -8 = 24$. Finally, subtract from 3: $3 - 24 = -21$.

Question 5

Evaluate.
-$(6-9)^{2} \div(-3)$
A) 0
B) $\frac{1}{3}$
C) -3
D) 3

Accepted Answer

First, calculate the expression inside the parentheses: $6-9 = -3$. Then, square the result: $(-3)^2 = 9$. Finally, divide by $-3$: $9 \div (-3) = -3$.

Question 6

Solve.
-On January 5 , the temperature at a camp site near the arctic circle was $4^{\circ}$ Fahrenheit. The temperature dropped $5^{\circ} \mathrm{F}$ per day for 12 days. What was the temperature on January 17 th?
A) $57^{\circ}$
B) $-56^{\circ}$
C) $-57^{\circ}$
D) $56^{\circ}$

Accepted Answer

The temperature dropped $5^{\circ} \mathrm{F}$ per day for 12 days, totaling a drop of $5^{\circ} \mathrm{F} \times 12 = 60^{\circ} \mathrm{F}$. Starting from $4^{\circ}$ Fahrenheit, the temperature on January 17th would be $4^{\circ} \mathrm{F} - 60^{\circ} \mathrm{F} = -56^{\circ} \mathrm{F}$.

Question 7

Solve.
-In 13 weeks, the value of Bob Treatman's day trading account decreased by $\$ 520$. What was the average weekly change in the value of the account expressed as a signed number?
A) $-\$ 40$ per week
B) $\$ 38$ per week
C) $-\$ 46$ per week
D) $-\$ 42$ per week

Accepted Answer

The average weekly change is found by dividing the total change by the number of weeks. Here, $-\$520 / 13 weeks = -\$40$ per week.

Question 8

Solve.
-The bar graph shows the percent change in stock over the past month for five different companies. Rank these companies in order from biggest loss to biggest gain in their stock prices.

A) Company E, Company A, Company C, Company D, Company B
B) Company E, Company A, Company C, Company B, Company D
C) Company C, Company A, Company E, Company B, Company D
D) Company C, Company A, Company E, Company D, Company B

Accepted Answer

The answer of Solve.
-The bar graph shows the percent change...

Question 9

Solve.
-The average summer temperature in the Antarctica was $-25^{\circ} \mathrm{F}$ and the average winter temperature was $-56^{\circ} \mathrm{F}$. How much higher was the summer average temperature?
A) $81^{\circ} \mathrm{F}$
B) $31^{\circ} \mathrm{F}$
C) $-81^{\circ} \mathrm{F}$
D) $-31^{\circ} \mathrm{F}$

Accepted Answer

To find how much higher the summer average temperature was compared to the winter average, subtract the winter average from the summer average: $-25^{\circ} \mathrm{F} - (-56^{\circ} \mathrm{F}) = 31^{\circ} \mathrm{F}$.

Quiz 7: Signed Numbers

Evaluate. - $\frac{1}{3} \div(-8)$

Evaluate. - $-19+(-10) +(-10) +21$

Evaluate. - $2+(-12) -(-14)$

Evaluate. - $3-(-3) \cdot(-2) ^{3}$

Evaluate. - $(6-9) ^{2} \div(-3)$

Solve. -On January 5 , the temperature at a camp site near the arctic circle was $4^{\circ}$ Fahrenheit. The temperature dropped $5^{\circ} \mathrm{F}$ per day for 12 days. What was the temperature on January 17 th?

Solve. -In 13 weeks, the value of Bob Treatman's day trading account decreased by $\$ 520$ . What was the average weekly change in the value of the account expressed as a signed number?

Solve. -The bar graph shows the percent change in stock over the past month for five different companies. Rank these companies in order from biggest loss to biggest gain in their stock prices.

Solve. -The average summer temperature in the Antarctica was $-25^{\circ} \mathrm{F}$ and the average winter temperature was $-56^{\circ} \mathrm{F}$ . How much higher was the summer average temperature?

Quiz 7: Signed Numbers

Evaluate. - 13÷(−8) \frac{1}{3} \div(-8) 31​÷(−8)

Evaluate. - −19+(−10) +(−10) +21-19+(-10) +(-10) +21−19+(−10) +(−10) +21

Evaluate. - 2+(−12) −(−14) 2+(-12) -(-14) 2+(−12) −(−14)

Evaluate. - 3−(−3) ⋅(−2) 33-(-3) \cdot(-2) ^{3}3−(−3) ⋅(−2) 3

Evaluate. - (6−9) 2÷(−3) (6-9) ^{2} \div(-3) (6−9) 2÷(−3)

Solve. -On January 5 , the temperature at a camp site near the arctic circle was 4∘4^{\circ}4∘ Fahrenheit. The temperature dropped 5∘F5^{\circ} \mathrm{F}5∘F per day for 12 days. What was the temperature on January 17 th?

Solve. -In 13 weeks, the value of Bob Treatman's day trading account decreased by $520\$ 520$520 . What was the average weekly change in the value of the account expressed as a signed number?