Solve using the principle of zero products.
-$\left(x+\frac{1}{4}\right)\left(x-\frac{2}{5}\right)=0$
A) 3,3
B) $-\frac{1}{4}, \frac{2}{5}$
C) $4, \frac{5}{2}$
D) $\frac{1}{4},-\frac{2}{5}$

Question

Quizplus · Accepted Answer

The principle of zero products states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, $x + \frac{1}{4} = 0$ gives $x = -\frac{1}{4}$, and $x - \frac{2}{5} = 0$ gives $x = \frac{2}{5}$.

Solve Using the Principle of Zero Products (x+14)(x−25)=0\left(x+\frac{1}{4}\right)\left(x-\frac{2}{5}\right)=0(x+41​)(x−52​)=0 A) 3,3 B) −14,25-\frac{1}{4}, \frac{2}{5}−41​,52​

Solve Using the Principle of Zero Products $\left(x+\frac{1}{4}\right)\left(x-\frac{2}{5}\right)=0$ A) 3,3
B) $-\frac{1}{4}, \frac{2}{5}$