Factor completely.
-$(\mathrm{m}+\mathrm{n})(\mathrm{x}+4)+(\mathrm{m}+\mathrm{n})(\mathrm{y}+6)$
A) $(m+n+10)(x+y)$
B) $(m+n+4)(x+y+6)$
C) $(m+n)(x+y+10)$
D) $(m+n)(2 x+10)$

Name: Factor completely. -$(\mathrm{m}+\mathrm{n})(\mathrm{x}+4)+(\mathrm{m}+\mathrm{n})(\mathrm{y}+6)$ A) $(m+n+10)(x+y)$ B) $(m+n+4)(x+y+6)$ C) $(m+n)(x+y+10)$ D) $(m+n)(2 x+10)$
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Question

Quizplus · Accepted Answer

The expression can be factored by factoring out the common factor $(m+n)$, resulting in $(m+n)((x+4)+(y+6))$, which simplifies to $(m+n)(x+y+10)$.