Let $\mathbf{A}=\left(\begin{array}{cc}1 & 2 \ 0 & -1\end{array}\right)$ and $\vec{u}=(5,-1)$. Find $\vec{w}$ such that $\vec{u}=\mathbf{A} \cdot \vec{w}$.

Name: Let $\mathbf{A}=\left(\begin{array}{cc}1 & 2 \\ 0 & -1\end{array}\right)$ and $\vec{u}=(5,-1)$. Find $\vec{w}$ such that $\vec{u}=\mathbf{A} \cdot \vec{w}$.
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The Answer of Let $\mathbf{A}=\left(\begin{array}{cc}1 & 2 \ 0 & -1\end{array}\right)$ and $\vec{u}=(5,-1)$. Find $\vec{w}$ such that $\vec{u}=\mathbf{A} \cdot \vec{w}$.

Let A=(120−1)\mathbf{A}=\left(\begin{array}{cc}1 & 2 \\ 0 & -1\end{array}\right)A=(10​2−1​) And u⃗=(5,−1)\vec{u}=(5,-1)u=(5,−1) Find w⃗\vec{w}w

Let $\mathbf{A}=\left(\begin{array}{cc}1 & 2 \\ 0 & -1\end{array}\right)$ And $\vec{u}=(5,-1)$ Find $\vec{w}$