Let $\mathbf{A}=\left(\begin{array}{ccc}1 & 2 & 0 \ -1 & 4 & -2 \ 0 & 2 & 3\end{array}\right)$ and $\mathbf{B}=\left(\begin{array}{ccc}4 & 3 & -2 \ 0 & 4 & 0 \ -1 & 1 & -1\end{array}\right)$
a) Find $\mathbf{A}+\mathbf{B}$
b) If $\vec{u}=(1,2,3)$, find $\mathbf{A} \vec{u}$.
c) If $\vec{v}=(-1,0,1)$, find $\overrightarrow{\mathbf{B}} \vec{v}$.

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The Answer of Let $\mathbf{A}=\left(\begin{array}{ccc}1 & 2 & 0 \ -1 & 4 & -2 \ 0 & 2 & 3\end{array}\right)$ and $\mathbf{B}=\left(\begin{array}{ccc}4 & 3 & -2 \ 0 & 4 & 0 \ -1 & 1 & -1\end{array}\right)$
a) Find $\mathbf{A}+\mathbf{B}$
b) If $\vec{u}=(1,2,3)$, find $\mathbf{A} \vec{u}$.
c) If $\vec{v}=(-1,0,1)$, find $\overrightarrow{\mathbf{B}} \vec{v}$.

Let A=(120−14−2023)\mathbf{A}=\left(\begin{array}{ccc}1 & 2 & 0 \\ -1 & 4 & -2 \\ 0 & 2 & 3\end{array}\right)A=​1−10​242​0−23​​

Let $\mathbf{A}=\left(\begin{array}{ccc}1 & 2 & 0 \\ -1 & 4 & -2 \\ 0 & 2 & 3\end{array}\right)$