Solve the system by the substitution method.
-$36 x^{2}+49 y^{2}=1764$
$7 y-6 x=42$
A) $(0,6),(-7,0)$
B) $(0,7),(0,-6)$
C) $(0,-6),(7,0)$
D) $(0,-7),(6,0)$

Question

Quizplus · Accepted Answer

First, solve the second equation for $y$: $7y = 6x + 42$, so $y = \frac{6}{7}x + 6$. Substitute $y$ in the first equation: $36x^2 + 49\left(\frac{6}{7}x + 6\right)^2 = 1764$. Simplify and solve for $x$, finding $x = 0$ or $x = -7$. Substitute $x$ back to find $y$, yielding solutions $(0,6)$ and $(-7,0)$.

Solve the System by the Substitution Method 36x2+49y2=176436 x^{2}+49 y^{2}=176436x2+49y2=1764 7y−6x=427 y-6 x=427y−6x=42

Solve the System by the Substitution Method $36 x^{2}+49 y^{2}=1764$ $7 y-6 x=42$