Find the standard-form equation of the hyperbola whose graph is shown.
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A) $\frac{(\mathrm{x}-2)^{2}}{16}-\frac{(\mathrm{y}+4)^{2}}{9}=1$
B) $\frac{(x+2)^{2}}{16}-\frac{(y-4)^{2}}{9}=1$
C) $\frac{(x+2)^{2}}{9}-\frac{(y-4)^{2}}{16}=1$
D) $\frac{(\mathrm{x}-2)^{2}}{9}-\frac{(\mathrm{y}+4)^{2}}{16}=1$

Question

Find the standard-form equation of the hyperbola whose graph is shown.
- 
A) $\frac{(\mathrm{x}-2)^{2}}{16}-\frac{(\mathrm{y}+4)^{2}}{9}=1$ 
B) $\frac{(x+2)^{2}}{16}-\frac{(y-4)^{2}}{9}=1$ 
C) $\frac{(x+2)^{2}}{9}-\frac{(y-4)^{2}}{16}=1$ 
D) $\frac{(\mathrm{x}-2)^{2}}{9}-\frac{(\mathrm{y}+4)^{2}}{16}=1$

Quizplus · Accepted Answer

The Answer of Find the standard-form equation of the hyperbola whose graph is shown.
- 
A) $\frac{(\mathrm{x}-2)^{2}}{16}-\frac{(\mathrm{y}+4)^{2}}{9}=1$ 
B) $\frac{(x+2)^{2}}{16}-\frac{(y-4)^{2}}{9}=1$ 
C) $\frac{(x+2)^{2}}{9}-\frac{(y-4)^{2}}{16}=1$ 
D) $\frac{(\mathrm{x}-2)^{2}}{9}-\frac{(\mathrm{y}+4)^{2}}{16}=1$

Find the Standard-Form Equation of the Hyperbola Whose Graph Is (x−2)216−(y+4)29=1\frac{(\mathrm{x}-2)^{2}}{16}-\frac{(\mathrm{y}+4)^{2}}{9}=116(x−2)2​−9(y+4)2​=1

Find the Standard-Form Equation of the Hyperbola Whose Graph Is $\frac{(\mathrm{x}-2)^{2}}{16}-\frac{(\mathrm{y}+4)^{2}}{9}=1$