Factor completely. If the polynomial cannot be factored, write "prime."
-$24 x^{2}+18 x-20 x-15$
A) $(24 x-5)(x+3)$
B) $(24 \mathrm{x}+5)(\mathrm{x}-3)$
C) $(6 x-5)(4 x+3)$
D) $(6 x+5)(4 x-3)$

Question

Quizplus · Accepted Answer

First, factor by grouping: $24x^2 + 18x - 20x - 15 = 6x(4x + 3) - 5(4x + 3)$. Then, factor out the common factor $(4x + 3)$, resulting in $(6x - 5)(4x + 3)$.

Factor Completely 24x2+18x−20x−1524 x^{2}+18 x-20 x-1524x2+18x−20x−15 A) (24x−5)(x+3)(24 x-5)(x+3)(24x−5)(x+3) B) (24x+5)(x−3)(24 \mathrm{x}+5)(\mathrm{x}-3)(24x+5)(x−3) C) (6x−5)(4x+3)(6 x-5)(4 x+3)(6x−5)(4x+3)

Factor Completely $24 x^{2}+18 x-20 x-15$ A) $(24 x-5)(x+3)$ B) $(24 \mathrm{x}+5)(\mathrm{x}-3)$ C) $(6 x-5)(4 x+3)$