Factor completely. If the polynomial cannot be factored, write "prime."
-$60 x^{6}+39 x^{4}+6 x^{2}$
A) $\left(12 x^{3}+3\right)\left(5 x^{3}+2\right)$
B) $3 x^{2}\left(5 x^{2}-2\right)\left(4 x^{2}-1\right)$
C) $3\left(4 x^{4}+1\right)\left(5 x^{2}+2\right)$
D) $3 x^{2}\left(4 x^{2}+1\right)\left(5 x^{2}+2\right)$

Question

Quizplus · Accepted Answer

First, factor out the greatest common factor, which is $3x^2$, resulting in $3x^2(20x^4 + 13x^2 + 2)$. Further factoring the quadratic inside gives $3x^2(4x^2+1)(5x^2+2)$.

Factor Completely 60x6+39x4+6x260 x^{6}+39 x^{4}+6 x^{2}60x6+39x4+6x2 A) (12x3+3)(5x3+2)\left(12 x^{3}+3\right)\left(5 x^{3}+2\right)(12x3+3)(5x3+2) B) 3x2(5x2−2)(4x2−1)3 x^{2}\left(5 x^{2}-2\right)\left(4 x^{2}-1\right)3x2(5x2−2)(4x2−1)

Factor Completely $60 x^{6}+39 x^{4}+6 x^{2}$ A) $\left(12 x^{3}+3\right)\left(5 x^{3}+2\right)$ B) $3 x^{2}\left(5 x^{2}-2\right)\left(4 x^{2}-1\right)$