Solve. Round results to the nearest thousandth.
-$7 \mathrm{x}^{2}=4-2 \mathrm{x}$
A) $0.626,-0.912$
B) $0.885,-0.599$
C) $0.599,-0.885$
D) $0.912,-0.626$

Question

Quizplus · Accepted Answer

To solve the equation $7x^2 = 4 - 2x$, first move all terms to one side to set the equation to 0: $7x^2 + 2x - 4 = 0$. Then, use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ with $a = 7$, $b = 2$, and $c = -4$. Plugging these values in gives $x = \frac{-2 \pm \sqrt{(2)^2 - 4(7)(-4)}}{2(7)}$, which simplifies to $x = \frac{-2 \pm \sqrt{4 + 112}}{14} = \frac{-2 \pm \sqrt{116}}{14}$. This further simplifies to $x = \frac{-2 \pm 10.7703}{14}$, leading to the solutions $x \approx 0.626$ and $x \approx -0.912$, rounded to the nearest thousandth.

Solve Round Results to the Nearest Thousandth 7x2=4−2x7 \mathrm{x}^{2}=4-2 \mathrm{x}7x2=4−2x A) 0.626,−0.9120.626,-0.9120.626,−0.912

Solve Round Results to the Nearest Thousandth $7 \mathrm{x}^{2}=4-2 \mathrm{x}$ A) $0.626,-0.912$