Solve. Round results to the nearest thousandth.
-$x^{2}+9 x=-9$
A) $7.854,1.146$
B) $0.908,-9.908$
C) $-1.146,-7.854$
D) $-5.646,-5.646$

Question

Quizplus · Accepted Answer

To solve the quadratic equation $x^{2} + 9x = -9$, first move all terms to one side to set the equation to 0: $x^{2} + 9x + 9 = 0$. Using the quadratic formula, $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, with $a = 1$, $b = 9$, and $c = 9$, we find the roots to be $x = -1.146$ and $x = -7.854$, rounded to the nearest thousandth.

Solve Round Results to the Nearest Thousandth x2+9x=−9x^{2}+9 x=-9x2+9x=−9 A) 7.854,1.1467.854,1.1467.854,1.146 B) 0.908,−9.9080.908,-9.9080.908,−9.908

Solve Round Results to the Nearest Thousandth $x^{2}+9 x=-9$ A) $7.854,1.146$ B) $0.908,-9.908$