Solve the problem.
-A rectangular garden is three times as long as it is wide. If the area of the garden is $588 \mathrm{ft}^{2}$, find the length and width of the garden.
A) length: $196 \mathrm{ft}$; width: $3 \mathrm{ft}$
B) length: $39 \mathrm{ft}$; width: $13 \mathrm{ft}$
C) length: $42 \mathrm{ft}$; width: $14 \mathrm{ft}$
D) length: $14 \mathrm{ft}$; width: $\frac{14}{3} \mathrm{ft}$

Question

Quizplus · Accepted Answer

The area of a rectangle is given by the formula $ \text{length} \times \text{width} $. If the length is three times the width, we can express this as $ \text{length} = 3 \times \text{width} $. Given the area is $588 \mathrm{ft}^{2}$, we set up the equation $3 \times \text{width} \times \text{width} = 588$. Solving for width, we find $ \text{width} = 14 \mathrm{ft} $ and thus the length is $ 3 \times 14 = 42 \mathrm{ft} $.

Solve the Problem 588ft2588 \mathrm{ft}^{2}588ft2 , Find the Length and Width of the Garden

Solve the Problem $588 \mathrm{ft}^{2}$ , Find the Length and Width of the Garden