Solve the problem.
-The product of two consecutive integers is 8 less than 8 times their sum. Find the integers.
A) 15,16
B) 0,1 or 15,16
C) 0,1 or 16,17
D) 0,1

Question

Quizplus · Accepted Answer

Let the two consecutive integers be $x$ and $x+1$. The equation based on the given information is $x(x+1) = 8(x + x + 1) - 8$. Simplifying gives $x^2 + x = 16x + 8 - 8$, which simplifies further to $x^2 - 15x = 0$. Factoring out $x$, we get $x(x - 15) = 0$, which gives the solutions $x = 0$ and $x = 15$. Therefore, the pairs of integers are $0,1$ and $15,16$.

Solve the Problem. -The Product of Two Consecutive Integers Is 8 Less Than