Factor completely.
-$50 x^{2}-8 y^{2}$
A) $(5 x+2 y)(10 x-4 y)$
B) $2(5 \mathrm{x}+2 \mathrm{y})(5 \mathrm{x}-2 \mathrm{y})$
C) $(10 x+4 y)(5 x-2 y)$
D) $2(5 x-2 y)^{2}$

Question

Quizplus · Accepted Answer

This expression is a difference of squares, which can be factored as $a^2 - b^2 = (a+b)(a-b)$. Here, $50x^2 = (5x)^2$ and $8y^2 = (2y)^2$, so the factorization is $2(5x+2y)(5x-2y)$.

Factor Completely 50x2−8y250 x^{2}-8 y^{2}50x2−8y2 A) (5x+2y)(10x−4y)(5 x+2 y)(10 x-4 y)(5x+2y)(10x−4y) B) 2(5x+2y)(5x−2y)2(5 \mathrm{x}+2 \mathrm{y})(5 \mathrm{x}-2 \mathrm{y})2(5x+2y)(5x−2y)

Factor Completely $50 x^{2}-8 y^{2}$ A) $(5 x+2 y)(10 x-4 y)$ B) $2(5 \mathrm{x}+2 \mathrm{y})(5 \mathrm{x}-2 \mathrm{y})$