Factor completely.
-$121 \mathrm{k}^{2}-49 \mathrm{~m}^{2}$
A) Prime
B) $(11 \mathrm{k}+7 \mathrm{~m})(11 \mathrm{k}-7 \mathrm{~m})$
C) $(11 \mathrm{k}+7 \mathrm{~m})^{2}$
D) $(11 \mathrm{k}-7 \mathrm{~m})^{2}$

Question

Quizplus · Accepted Answer

This expression is a difference of squares, factoring into $(11k)^2 - (7m)^2 = (11k + 7m)(11k - 7m)$.

Factor Completely 121k2−49 m2121 \mathrm{k}^{2}-49 \mathrm{~m}^{2}121k2−49 m2 A) Prime B) (11k+7 m)(11k−7 m)(11 \mathrm{k}+7 \mathrm{~m})(11 \mathrm{k}-7 \mathrm{~m})(11k+7 m)(11k−7 m)

Factor Completely $121 \mathrm{k}^{2}-49 \mathrm{~m}^{2}$ A) Prime
B) $(11 \mathrm{k}+7 \mathrm{~m})(11 \mathrm{k}-7 \mathrm{~m})$