Factor using the ac-method.
-$6 x^{2}+17 x+12$
A) prime
B) $(6 x+3)(x+4)$
C) $(2 x-3)(3 x-4)$
D) $(2 x+3)(3 x+4)$

Question

Quizplus · Accepted Answer

The ac-method involves multiplying the coefficient of $x^2$ (which is 6) by the constant term (which is 12) to get 72. We then find two numbers that multiply to 72 and add to 17, which are 9 and 8. Rewriting the middle term, we have $6x^2 + 9x + 8x + 12$. Factoring by grouping, we get $3x(2x + 3) + 4(2x + 3)$, which factors to $(2x + 3)(3x + 4)$.

Factor Using the Ac-Method 6x2+17x+126 x^{2}+17 x+126x2+17x+12 A) Prime B) (6x+3)(x+4)(6 x+3)(x+4)(6x+3)(x+4)

Factor Using the Ac-Method $6 x^{2}+17 x+12$ A) Prime
B) $(6 x+3)(x+4)$