Factor by grouping.
-$8 x^{2}-20 x y+10 x y-25 y^{2}$
A) $(8 x+5 y)(x-5 y)$
B) $(4 \mathrm{x}+5)(2 \mathrm{x}-5)$
C) $(4 x+5 y)(2 x-5 y)$
D) $(4 x-5 y)(2 x-5 y)$

Name: Factor by grouping. -$8 x^{2}-20 x y+10 x y-25 y^{2}$ A) $(8 x+5 y)(x-5 y)$ B) $(4 \mathrm{x}+5)(2 \mathrm{x}-5)$ C) $(4 x+5 y)(2 x-5 y)$ D) $(4 x-5 y)(2 x-5 y)$
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Question

Quizplus · Accepted Answer

First, factor by grouping: $8x^2 - 20xy + 10xy - 25y^2 = 4x(2x - 5y) + 5y(2x - 5y)$. Then, factor out the common factor $(2x - 5y)$, resulting in $(4x + 5y)(2x - 5y)$.

Factor by Grouping 8x2−20xy+10xy−25y28 x^{2}-20 x y+10 x y-25 y^{2}8x2−20xy+10xy−25y2 A) (8x+5y)(x−5y)(8 x+5 y)(x-5 y)(8x+5y)(x−5y)

Factor by Grouping $8 x^{2}-20 x y+10 x y-25 y^{2}$ A) $(8 x+5 y)(x-5 y)$