Solve the problem.
-A rectangular Persian carpet has a perimeter of 232 inches. The length of the carpet is 20 inches more than the width. What are the dimensions of the carpet?
A) $68 \mathrm{in} ., 88 \mathrm{in}$.
B) $48 \mathrm{in.}, 68 \mathrm{in}$.
C) $106 \mathrm{in} ., 126 \mathrm{in}$.
D) 96 in., 116 in.

Question

Quizplus · Accepted Answer

The perimeter of a rectangle is given by $2l + 2w$, where $l$ is the length and $w$ is the width. Given that the length is 20 inches more than the width ($l = w + 20$), and the perimeter is 232 inches, we can set up the equation $2(w + 20) + 2w = 232$. Simplifying, we get $4w + 40 = 232$, then $4w = 192$, and finally $w = 48$. Substituting back to find $l$, $l = 48 + 20 = 68$. Therefore, the dimensions are 48 inches by 68 inches.

Solve the Problem 68in.,88in68 \mathrm{in} ., 88 \mathrm{in}68in.,88in B) 48in.,68in48 \mathrm{in.}, 68 \mathrm{in}48in.,68in

Solve the Problem $68 \mathrm{in} ., 88 \mathrm{in}$
B) $48 \mathrm{in.}, 68 \mathrm{in}$