Solve the problem.
-Find the length of a rectangular lot with a perimeter of 126 meters if the length is 7 meters more than the width. $(\mathrm{P}=2 \mathrm{~L}+2 \mathrm{~W})$
A) $35 \mathrm{~m}$
B) $28 \mathrm{~m}$
C) $63 \mathrm{~m}$
D) $70 \mathrm{~m}$

Question

Quizplus · Accepted Answer

The perimeter formula is $P = 2L + 2W$, where $P = 126$, $L = W + 7$. Substituting $L$ into the perimeter formula gives $126 = 2(W + 7) + 2W$, simplifying to $126 = 4W + 14$, and solving for $W$ gives $W = 28$. Thus, $L = W + 7 = 35$ meters.

Solve the Problem (P=2 L+2 W)(\mathrm{P}=2 \mathrm{~L}+2 \mathrm{~W})(P=2 L+2 W) A) 35 m35 \mathrm{~m}35 m B) 28 m28 \mathrm{~m}28 m C) 63 m63 \mathrm{~m}63 m

Solve the Problem $(\mathrm{P}=2 \mathrm{~L}+2 \mathrm{~W})$ A) $35 \mathrm{~m}$ B) $28 \mathrm{~m}$ C) $63 \mathrm{~m}$