Consider the Following Periodic Function with Period :
F $a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots$

Consider the following periodic function with period :
F (t) =
F = f (t)
The Fourier representation has the form
Which of these are the coefficients ?

A) $a_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots$
B) $a_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots$
C) $a_{2 n}=0, a_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots$
D) $a_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, a_{2 n-1}=0, n=1,2,3, \ldots$
E) $a_{n}=0, n=1,2,3, \ldots$