An electron, initially moving at 2.0 × 10⁴ m/s along the +x-axis, experiences a constant acceleration of 1010 m/s² in the +y direction. How far from its starting point is the electron after 4.0 × 10^-6 seconds? A) 8.0 m B) 11.3 m C) 11.3 cm D) 8.0 cm E) 9.8 m

Question

Quizplus · Accepted Answer

The electron moves in the x-direction with constant velocity and in the y-direction with constant acceleration. The distance in the x-direction is (2.0 × 10^4 m/s) × (4.0 × 10^-6 s) = 0.08 m. The distance in the y-direction is (1/2) × (1010 m/s²) × (4.0 × 10^-6 s)² = 8.08 × 10^-6 m. The total distance is √((0.08 m)² + (8.08 × 10^-6 m)²) ≈ 0.113 m or 11.3 cm.

An Electron, Initially Moving at 2